Question 546953
{{{drawing(300,300,-12,12,-12,12,
circle(0,0,10), rectangle(-8.66,-8.66,8.66,8.66),
line(-8.66,-8.66,8.66,8.66),line(-8.66,8.66,8.66,-8.66),
line(0,0,-5,-8.66),line(0,0,5,-8.66),line(0,0,0,-8.66),
locate(-5,-8.66,A),locate(5,-8.66,B),locate(-0.2,1.5,C),
locate(-8.66,-8.66,E),locate(8.66,-8.66,F),locate(0,-8.66,D)
)}}} {{{r=AB=AC=BC}}}, {{{AD=r/2}}}, {{{ED=DF=CD=sqrt(3)*r/2}}}, {{{EF=sqrt(3)*r}}}
The area for the square is {{{(EF)^2=(sqrt(3)*r)^2=3r^3}}}
The area for the circle is {{{pi*r^2}}}.
The ratio would be {{{3/pi}}}