Question 546969
Find the area of a triangle with sides 5, 8, 10. No decimals. Exact answer with a radical but no trigonometric functions. 
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Use Heron's Law:
{{{area = sqrt(s*(s-5)*(s-8)*(s-10))}}} where s = 1/2 the perimeter = 23/2
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{{{area = sqrt((23/2)*(13/2)*(7/2)*(3/2)) = sqrt(6279/16)}}}
= {{{sqrt(6279)/4}}} sq units