Question 542681
write each expression as a single logarithm. 
2log4 - log6 + 3log2
**
2log4 - log6 + 3log2
log4^2 - log6 + log2^3
addition in logs indicate multiplication; subtraction indicates division
log[(4^2*2^3)/6]=log(128/6)=log(64/3)
2log4-log6+3log2=log(64/3)