Question 544145
Solve for x.
logx+log(x+3)=1
**
log[x*(x+3)]=1
log(x^2+3x)=1
convert to exponential form:
10^1=x^2+3x
x^2+3x-10=0
(x+5)(x-2)=0
x=-5 (reject, x>0)
or
x=2