Question 546385
If the width of the kitchen is 75% of the 20-foot length, the kitchen width, in feet is
{{{0.75*20=15}}}
The floor surface (in square feet) would be
{{{15*20=300}}}The countertops can be at most 1/20 of that or (in square feet)
{{{15*20*(1/20)=15}}}.
If the countertops take that much space in straight stretches (no L shapes) with 2 ft width, then their total length will be {{{15ft^2/2ft=7.5ft}}}
If all but the 15 square feet taken up by the countertops is to be tiled, you need to tile {{{300-15=285}}} square feet. Your 6-inch tiles are 0.5 ft long, with 0.25 square feet of surface, and you need 4 of those to cover 1 square foot of floor, so to cover 285 square feet, you'd need
{{{285*4=1140}}} tiles.