Question 545749
log(6x+5)=1+log(x-8)
log(6x+5)-log(x-8)=1
log[(6x+5)/(x-8)]=1
exponential form: base(10) raised to log of number(1)=number[(6x+5)/(x-8)]
10^1=(6x+5)/(x-8)=10
6x+5=10x-80
4x=85
x=21.25