Question 546237
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-8,-4\right)]. So this means that {{{x[1]=-8}}} and {{{y[1]=-4}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(2,-7\right)].  So this means that {{{x[2]=2}}} and {{{y[2]=-7}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-7--4)/(2--8)}}} Plug in {{{y[2]=-7}}}, {{{y[1]=-4}}}, {{{x[2]=2}}}, and {{{x[1]=-8}}}



{{{m=(-3)/(2--8)}}} Subtract {{{-4}}} from {{{-7}}} to get {{{-3}}}



{{{m=(-3)/(10)}}} Subtract {{{-8}}} from {{{2}}} to get {{{10}}}



So the slope of the line that goes through the points *[Tex \LARGE \left(-8,-4\right)] and *[Tex \LARGE \left(2,-7\right)] is {{{m=-3/10}}}