Question 53337
find the perimeter of a triangle of sides 6x-4, x^2+2(1-2x) and x(x-1) in terms of x.
P=6X-4+X^2+2(1-2X)+X(X-1)=6X-4+X^2+2-4X+X^2-X=2X^2 + X - 2