Question 546172


Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(6,-7\right)]. So this means that {{{x[1]=6}}} and {{{y[1]=-7}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(9,-9\right)].  So this means that {{{x[2]=9}}} and {{{y[2]=-9}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-9--7)/(9-6)}}} Plug in {{{y[2]=-9}}}, {{{y[1]=-7}}}, {{{x[2]=9}}}, and {{{x[1]=6}}}



{{{m=(-2)/(9-6)}}} Subtract {{{-7}}} from {{{-9}}} to get {{{-2}}}



{{{m=(-2)/(3)}}} Subtract {{{6}}} from {{{9}}} to get {{{3}}}



So the slope of the line that goes through the points *[Tex \LARGE \left(6,-7\right)] and *[Tex \LARGE \left(9,-9\right)] is {{{m=-2/3}}}