Question 545445
Solve.
4log₃2 - 2log₂x = 1
log3(2^4)-log2(x^2)=1
log3(16)-log2(x^2)=1
change to base 10
log(16)/log(3)-log(x^2)/log(2)=1
2.5237-log(x^2)/log(2)=1
2.5237-1=log(x^2)/log(2)
1.5237*log(2)=log(x^2)
.4587=log(x^2)
x^2=10^.4587=2.8754
x≈1.696
note: I tried solving without using a calculator but maybe a smarter tutor might know how.