Question 545618
log(base 3)x + log(base 3)(x - 2) = 1
log3(x)+log3(x-2)=1
place under single log (addition in logs indicates multiplication in operations)
log[x*(x-2)]=1
log[x^2-2x]=1
convert to exponential form: base(3) raised to log of number(1)=number[x^2-2x]
3^1=[x^2-2x]
x^2-2x-3=0
(x-3)(x+1)=0
x=3
or
x=-1(reject, x>0)
ans: x=3