Question 546072
Okay, first we need to find the equation of the line of 8x+3y=7, which is in standard form.
First, get the x variable on the right and change the sign
3y=-8x+7

Then divide all terms by 3

y=-8/3x+7/3

Now, perpendicular lines have the reciprical slope and different sign, plus the same y intercept

The point slope formula is y-y1=m(x-x1)
basically, all this is is y (the variable)+ the y axis coordinate (in this case 7). Equalls the slope times x minus the x axis coordinate (in this case 0)

First get the perpendicular equation of the line:

y=3/8x+7/3

Now plug in all numbers:

y-7=3/8(x-0)

Solve.

y-7=3/8x-0

Answer:
y=3/8x+7