Question 546018
a. index 3 (radicand 2x + 1) = 1
I think you mean
{{{root(3,(2x + 1)) = 1}}}
2x + 1 = 1
x = 0
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b. (radicand x + 2) = x -3
{{{sqrt(x+2) = x-3}}}
{{{x+2 = x^2 - 6x + 9}}}
{{{x^2 - 7x + 7 = 0}}}
*[invoke solve_quadratic_equation 1,-7,7]
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c.  x ^ 1/3 = 3 = 0
too many equal signs.