Question 545909
Let d = the diameter of the smaller circle
Then the larger circle has diameter = {{{(3/2)d}}}
The area of a circle = {{{pi*r^2}}}
So the area of the smaller circle = {{{pi*(d/2)^2}}}
And the area of the larger circle = {{{pi*((3/2)d/2)^2}}}
When we take the ratio, we are left with (3/2)^2 = 9/4
Ans: D.