Question 545801
{{{x=n+q+d+p}}} total (x) amount = (n)ickels + (q)uarters + (d)imes + (p)ennies
***{{{n+16=x}}} <--- amount of nickels plus 16 coins = total amount of coins
{{{16=q+d+p}}} this means that the other 16 coins are made up of quarters dimes and pennies
{{{q+16=x}}} amount of quarters plus 16 coins = total amount of coins
{{{16=n+d+p}}} this means that the other 16 coins are made up of nickels dimes and pennies
{{{d+16=x}}} amount of dimes plus 16 coins = total amount of coins
{{{16=n+q+p}}} this means that the other 16 coins are made up of nickels quarters and pennies
{{{p+18=x}}} amount of pennies plus 18 coins = total amount of coins
{{{18=n+q+d}}} this means that the other 18 coins are made up of nickels quarters and dimes 
.
Deducing from above set values of x against values of x to find what each amount is equal to
{{{x=x}}}
{{{n+16=q+16}}}
{{{n=q}}}
d+16=n+16=q+16
d=n=q   so the amount of dimes/nickels/quarters are all the same amount
this means its like saying {{{n+n+n+p=x}}}
***{{{3n+p=x}}} <--- I chose (n)ickels as it was the first equation
{{{p+18=n+16}}}
***{{{p=n-2}}} <---
{{{3n+(n-2)=n+16}}} combining the 3 (***)<--- values I made this equation.
{{{4n-2=n+16}}}
{{{3n=18}}}
{{{highlight(n=6)}}} if n=6 then:
{{{highlight(q=6)}}}
{{{highlight(d=6)}}}
{{{highlight(p=4)}}}
.
check
{{{x=n+q+d+p}}}
{{{22=6+6+6+4}}}
{{{n+16=x}}} {{{q+16=x}}} {{{d+16=x}}} {{{p+18=x}}} 
{{{n+16=22}}} {{{q+16=22}}} {{{d+16=22}}} {{{p+18=22}}} 
{{{n=6}}} {{{q=6}}} {{{d=6}}} {{{p=4}}} 
Correct