Question 545822
What is the highest possible price for a bottle of the beer if it has to be
under $4 and its price in cents is gotten by multiplying the number of cents by
4, its number of dollars by 3, and adding the two results?
<pre>
The number of dollars has to be 3 for the beer to be under $4.

Let C = the number of cents

4×(the number of cents) + 3×(the number of dollars) < 400

4×C + 3×3 < 400

   4C + 9 < 400

Subtract 9 from both sides

       4C < 391

Divide both sides by 4

        C < 97.75

We must have a whole number of cents, so the
largest whole number of cents possible is 97.

So the highest possible price for the beer is 

4×97 + 3×3 = 388 + 9 = 397 cents which is $3.97

Edwin</pre>