<PRE><B>Question 545741</B>
&lt;br&gt;&lt;font face=&quot;Tahoma&quot;&gt;To write any LINEAR equation in slope-intercept form,&lt;br&gt;

you need only to solve for y!&lt;br&gt;

{{{2x-3y=6}}} given&lt;br&gt;

{{{2x=3y+6}}} added 3y to both sides&lt;br&gt;

{{{2x-6=3y}}} subtracted 6 from both sides&lt;br&gt;

{{{2x/3-2=y}}} divided both sides by 3&lt;br&gt;

{{{y=2x/3-2}}} which is what we need&lt;br&gt;

It is now in the slope-intercept form {{{y=mx+b}}}&lt;br&gt;

So from our new equation, we know:&lt;br&gt;

slope is m which equals 2/3&lt;br&gt;

y-intercept is b which is -2, or the point (0,-2)&lt;br&gt;

I hope this helps!  :)&lt;br&gt;</PRE>