Question 545651
{{{ 2 + 3*log(x) + (1/3)*log(4-x) - log(7) - 2*log(x+7)  }}}
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You need to use the rules:
{{{ log(a) + log(b) + log(c) = log( a*b*c ) }}}
{{{ a*log(b) = log(a^b) }}}
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Everything in the given expression needs to be
in the form of {{{ log(a) }}}, so I change {{{2}}}
{{{ 2 = log(100) }}}. This just says {{{ 10^2 = 100 }}}
{{{ log(100) + 3*log(x) + (1/3)*log(4-x) - log(7) - 2*log(x+7)  }}}
{{{ log(100) + log(x^3) + log((4-x)^(1/3)) - log(7) - log((x+7)^2) }}}
{{{ log( (100*(x^3)*(4-x)^(1/3)) / (7*(x + 7)^2) ) }}}
I'm not sure what to do now, but I believe this is
the right approach.