Question 545623
{{{q = p / sqrt((p^2)+1)}}}

take the square of both sides

{{{q^2=p^2/(p^2+1)}}}

{{{(p^2+1)/p^2=1/q^2}}}

{{{(p^2/p^2) +(1/p^2)= 1/q^2}}}

{{{1+(1/p^2)=1/q^2}}}

{{{1/p^2= ((1/q^2)-1))}}}

{{{1/p^2=(1-q^2)/q^2}}}

{{{p^2=q^2/(1-q^2)}}}

Take the square root

{{{p=+(q/(sqrt(1-q^2)))}}}

OR

{{{p=-(q/(sqrt(1-q^2)))}}}

m.ananth@hotmail.ca