Question 545578
{{{-16t^2+80t+6}}}
1) Basic physics formula for anything that has initial velocity is 
{{{-16(t)^2+vt+h}}} t= number of seconds; x= inital velocity (i.e. how hard was it thrown); h= initial height 
2)Plug three in where you see a "t"
{{{-16(3)^2+80(3)+6}}}
3) Square then multiply
{{{-16(9)+80(3)+6}}}
{{{-144+240+6}}}
4) Simplify
{{{102}}}
5) At three seconds the ball is 102ft off the ground