Question 545560
{{{y+3=3(x-1)}}}
1) Slope-Int form is y=mx+b; m=slope; b=y-intercept
2) Move the three from the left to the right by subtracting three to both sides
{{{y=3(x-1)-3}}}
3) Distribute the first three into (x-1)
{{{y=3x-3-3}}}
4) Simplify
{{{y=3x-6}}}
5) This shows that the line has a slope of three and has a y-int or point at (0,-6)