Question 545230
The way I see it, there is the ellipse formed by the hole in the wall, with a smaller ellipse inside, at the visible edge of the glass. In between them there is a frame that is 2 inches wide.
That makes the visible part of the glass 8 inches tall (12-2-2) and 20 inches wide (24-2-2). Those are the minor and major axes of the ellipse. The equation will involve the semi-axes (half of 8 and 20, meaning 4 and 10).
The equation for an ellipse centered at the origin, can be written as
{{{x^2/a^2+y^2/b^2=1}}}, where a and b are the semi-axes in the x and y directions
If we put the origin of our system of coordinates at the very center of the glass, with x for horizontal coordinate, and y for vertical coordinate, the edge of the glass will have the equation
{{{x^2/10^2+y^2/4^2=1}}}<-->{{{x^2/100+y^2/16=1}}}
At the tallest point {{{x=0}}}, the edge of the glass will be at
{{{y^2/4^2=1}}}<-->{{{y^2=4^2}}}<--> y=-4 and y=4 (8 inches tall).
At the widest point {{{y=0}}}, the edge of the glass will be at
{{{x^2/10^2=1}}}<-->{{{x^2=10^2}}}<--> x=-10 and x=10 (20 inches wide).