Question 545163
The function is a polynomial function, and polynomial functions are continuous. So your intermediate value theorem tells you that between x=1 and x=2, f(x) will take all the values between f(1) and f(2). For any value you pick, between f(1) and f(2), there will be a point x=c, where the function will take that value. (You can always calculate an approximation for that x=c, by trial and error, but it may not be easy, and you may not be able to calculate the exact value).
{{{f(1)=8*1^5-4*1^3-9*1^2-9=8-4-9-9=-14<0}}}
{{{f(2)=8*2^5-4*2^3-9*2^2-9=8*32-4*8-9*4-9=256-32-36-9=179>0}}}
Since {{{f(1)<0}}} and {{{f(2)>0}}}, {{{f(1)<0<f(2)}}}.
In other words, zero is between f(1) and f(2).
So the function has to go through zero at some point in the interval (1,2).
If f(1) and f(2) were both positive, or both negative, you would not know if the function had a zero in (1,2).