Question 544933
Find the cos of theta if csc = 2/sqrt(3) and theta terminates in Q4
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csc and sin<0 in Q4, cos>0 in Q4
cscx=-2/&#8730;3
sinx=-&#8730;3/2 (reciprocal of csc)
cos^2x=1-sin^2x=1-(-&#8730;3/2)^2=1-3/4=1/4
cosx=&#8730;(1/4)=1/2