Question 545127
Solve for x:
{{{Log[6](x+1) = 3}}} Rewrite this in "exponential" form: {{{Log[b](x) = y}}}---->{{{b^y = x}}}
{{{6^3 = x+1}}}
{{{216 = x+1}}} Subtract 1.
{{{215 = x}}} or {{{x = 215}}}