Question 545107
Solve for x:
{{{Log(8) = Log(x)+Log(2x)}}} Apply the "Product rule" to the right side:
{{{Log[b](M)+Log[b](N) = Log[b](M*N)}}}.
{{{Log(8) = Log(x*2x)}}}
{{{Log(8) = Log(2x^2)}}} If {{{Log[b](M) = Log[b](N)}}} then {{{M = N}}}
{{{8 = 2x^2}}} Divide by 2.
{{{4 = x^2}}} Take the square root.
{{{2 = x}}} or {{{x = 2}}}