Question 544577
{{{(n^4-4n^3+n-4)/(n-4)}}}?
You could use long division, but factoring seems easier.
{{{(n^4-4n^3+n-4)/(n-4)=((n^4-4n^3)+(n-4))/(n-4)=(n^3*(n-4)+1*(n-4))/(n-4)=((n^3+1)*(n-4))/(n-4)=n^3+1}}}
I'm sorry. I do not know how I could post anything remotely resembling pencil and paper long division. The result would be the same, of course.