<PRE><B>Question 544740</B>
24y^2+2y-2 = 0

Divide every term by 2.

2(12y^2 + y - 1) = 0


12y^2 + y - 1 = 0


12y^2 + 4y - 3y - 1 = 0


12y^2 + 4y becomes 4y(3y + 1)


-3y - 1 becomes -(3y + 1)


(4y - 1)(3y + 1) = 0


Set each factor to zero and solve for y.


4y - 1 = 0


4y = 1


y = 1/4


3y + 1 = 0


3y = -1


y = -1/3


The answer for y should be y = 1/4 and y = -1/3.


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