Question 544125
{{{(x-6)^2=64}}}
{{{(x-6)(x-6)=64}}}
{{{x^2-12x+36=64}}}
{{{x^2-12x-28=0}}}
{{{x-14)(x+2)=0}}}
{{{x-14=0}}}{{{x+2=0}}}
{{{x=14}}}{{{x=-2}}}
sum of the x values:
{{{14+(-2)=highlight(12)}}}