Question 544491
1	y  	=	3	x	+	5	
Divide by 	1						
	y  	=	3    	x	+	5	
Compare this equation with y=mx+b							
slope m =	3    						
The slope of a line parallel to the above line will be the same							
The slope of the required line will be 			3    				
m=	3    	,point	(	-4	,	1	)
Find b by plugging the values of m & the point in							
y=mx+b							
1	=	-12      	+	b			
b=	13						
m=	3    						
Plug value of  the slope  and b	in y = mx +b		
The required equation isy  	=	3    	x	+	13 

For perpendicular line the slope will be negative reciprocal.
which is -1/3
the line passes through (-4,1)
y= mx +b
1=-1/3(-4)+b  
1=4/3+b
b=-1/3
The equation will be y= -(1/3) x -1/3
   
		  
m.ananth@hotmail.ca