Question 544476
I would just transform the mixed numbers into improper fractions:
{{{(3&1/2)=3+1/2=6/2+1/2=7/2}}}
{{{(3&1/3)=3+1/3=9/3+1/3=10/3}}}
I would not be able to multiply those numbers any other way. 
{{{(3&1/2)*(3&1/3)=(7/2)*(10/3)=7*10/(2*3)=7*2*5/(2*3)=7*cross(2)*5/(cross(2)*3)=35/3=11&2/3}}}