Question 544383
The units digit of a two-digit number is 2 less than the square of the tens digit. If 36 is added to the number, the result is the number with the digits reversed. Find the original number.
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let u=units digit
let t=tens digit
u=t^2-2
10t+u+36=10u+t
10t+(t^2-2)+36=10(t^2-2)+t
10t+t^2-2+36=10t^2-20+t
10t+t^2+34=10t^2-20+t
9t^2-9t-54=0
t^2-t-6=0
(t-3)(t+2)=0
t=-2 (reject)
or 
t=3
u=t^2-2=9-2=7
original number: 37
Check: 37+36=73