<PRE><B>Question 544158</B>
{{{1/(4x + 2)}}} - {{{x/3}}} = {{{(-21)/(10x + 5)}}}
Factoring the denominators will help
{{{1/(2(2x + 1))}}} - {{{x/3}}} = {{{(-21)/(5(2x + 1))}}}
:
get rid of the some of the denominators, multiply by 30, results:
{{{15/((2x + 1))}}} - 10x = {{{6(-21)/((2x + 1))}}}
{{{15/((2x + 1))}}} - 10x = {{{(-126)/((2x + 1))}}}
:
Multiply by (2x+1) and you have
15 - 10x(2x+1) = -126
-20x^2 - 10x = -126 - 15
-20x^2 - 10x = -141
:
Get rid of all those negatives, mult by -1
20x^2 + 10x = +141
20x^2 + 10x - 141 = 0
Solve this quadratic equation using the quadratic formula
I got: x = 2.417 and x = -2.917
these look like unlikely solutions, however, I check them both out in the original problem and got equality.
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