Question 544073
{{{a^2+b^2=c^2}}}
a=length
b=width
c=diagnal
if a=2b and c=8 then solve for b
{{{a^2+b^2=c^2}}}
{{{(2b)^2+b^2=(8)^2}}}
{{{4b^2+b^2=64}}}
{{{5b^2=64}}}
{{{b^2=(64/5)}}}
{{{sqrt(b^2)=sqrt(64/5)}}}
{{{b=sqrt(64)/sqrt(5)}}}
{{{highlight(b=8/sqrt(5))}}}
{{{a=2b}}}
{{{a=2(8/sqrt(5))}}}
{{{highlight(a=16/sqrt(5))}}}

check
{{{a^2+b^2=c^2}}}
{{{(16/sqrt(5))^2+(8/sqrt(5))^2=8^2}}}
{{{(256/5)+(64/5)=64}}}
{{{256+64=320}}}
{{{320=320}}}
Correct