Question 6409
Plug in the point(-3,4) in the equation for x and y.

	A(-3) + B(4) = 11
	-3A + 4B = 11------(1)

	Plug in the point (2,1) in the equation.

	A(2) + B(1) = 11
	2A + B = 11------(2)

	From (2)    2A + B = 11
	Subtracting 2A on both sides, 

	2A + B – 2A = 11 – 2A
		   B = 11 – 2 A

	Plugging this in (1), we get, 
	-3A + 4( 11-2A = 11
	-3A + 44 – 8A = 11
	-11A 	= – 33
	  A = 3

	Plug in the value of A in any one of  the equation (1) and (2)

	2A + B = 11
	2(3) + B = 11
	6 + B = 11
	     B = 11 – 6 = 5.

	So A = 3 and B =5 is the solution.