Question 543613
I notice that {{{ 1/25 = (1/5)^2 }}}
If I say {{{ a = 1/5 }}} ,then I have
{{{ x^2 - 2a*x + a^2 }}}
{{{ ( x - a )^2 }}}
There are 2 identical roots, {{{ x = a }}} and
since {{{ a = 1/5 }}},
{{{ x = 1/5 }}}
check answer:
{{{ x^2 - (2/5)*x + (1/5)^2 = 0 }}}
{{{ (1/5)^2 - (2/5)*(1/5) + (1/5)^2 = 0 }}}
{{{ 1/25 - 2/25 + 1/25 = 0 }}}
{{{ 2/25 - 2/25 = 0 }}}
{{{ 2/25 = 2/25 }}}
OK