<PRE><B>Question 543176</B>
The age of a person is twice the sum of the ages of his two sons and five years ago his age was thrice the sum of their ages.find  his present age.
**
let x=present age of father
let y=sum of ages of two sons
..
At present:
x=2y
5 years ago:
x-5=3(y-10)
substitute 2y for x
2y-5=3y-30
y=25
x=2y=50
Ans:
Present age of father=25</PRE>