Question 539439
My understanding is that for substitution method, you just plug in the "Y=" formula were Y used to be and solve.
.
If {{{Y=2x+1}}}
then
{{{x+y=4}}}
{{{x+(2x+1)=4}}}
{{{x+2x+1=4}}}
{{{3x=3}}}
{{{x=1}}}
.
Then plug that answer back into the Y= formuala
.
{{{Y=2x+1}}}
{{{Y=2(1)+1}}}
{{{Y=2+1=3}}}
.
So your answer is, x=1 and y=3. (1,3)