Question 543094
"Stack" and reduce
1) {{{x+3y=6}}}
2) {{{4x-5y=7}}}
make both have the same # of X's or Y's. Since it's easier w/ X, multiply #1 by 4
1) {{{4x+12y=24}}}
2) {{{4x-5y=7}}}
Subtract #2 from #1, don't forget the 5y is negative (-- = +)
{{{17y=17}}}
{{{y=1}}}
.
Therefore
{{{x+3y=6}}}
{{{x+3(1)=6}}}
{{{x+3=6}}}
{{{x=3}}}