Question 543125
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I think you are trying to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x\ +\ 8}{x}\ =\ 9^2]


And that is absolutely correct -- so far.  Then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{x\ +\ 8}{x}\ =\ 81]


Multiply both sides by *[tex \Large x]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 8 =\ 81x]


Add *[tex \Large -x] to both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 80x\ =\ 8]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ 0.1]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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