Question 542984
If I call the height from which it was hit {{{ h = 0 }}}
The equation for height is {{{ h = -16t^2 + v[0]*t }}}
where {{{ v[0] }}} is the initial velocity.
{{{h}}} is the height in ft
{{{t}}} is the time in sec
At {{{ h=0 }}}, {{{ t = 0 }}} or {{{ t=6 }}}
For {{{ t = 6 }}},
{{{ 0 = -16*6^2 + v[0]*6 }}}
{{{ 6v[0] = 16*36 }}}
{{{ v[0] = 96 }}}
The equation is
{{{ h = -16t^2 + 96t }}}
The ball takes just as long to rise as it does to fall, so
the maximum height is at {{{ t = 3 }}} sec
{{{ h[max] = -16*3^2 + 96*3 }}}
{{{ h[max] = -16*9 + 96*3 }}}
{{{ h[max] = -16*9 + 32*9 }}}
{{{ h[max] = ( 32 - 16 )*9 }}}
{{{ h[max] = 144 }}}
The maximum height is 144 ft