Question 542957
Solve the equation 
log3 x^2 - log3(3x+18)=0
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log3[x^2/(3x+18)] = 0
x^2/(3x+18) = 3^0 = 1
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x^2 = 3x+18
x^2-3x-18 = 0
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Factor:
(x-6)(x+3) = 0
x = 6 or x = -3
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Cheers,
Stan H.