Question 542525
You must have been taught that multiplying numbers in polar form is easier, because all you have to do is multiply one modulus times the other and add the arguments.
{{{abs(z^3)=abs(z)^3=2^3=8}}} and {{{arg(z^3)=3*arg(z)=3Q)}}}
If you have not been taught anything about exponents on complex numbers, this problem is a way of introducing de Moivre's formula for the nth power of a complex number.