<PRE><B>Question 542357</B>
&lt;br&gt;&lt;font face=&quot;Tahoma&quot;&gt;When dealing with right triangles you can always use Pythagorean&#39;s Theorem.&lt;br&gt;

Or you can simply remember that the ratio of the sides of a 45-45-90 triangle is:&lt;br&gt;

{{{1:1:sqrt(2)}}} with the hypotenuse being the longest leg of course.&lt;br&gt;

In this case, we have:&lt;br&gt;

{{{x:x:16}}}&lt;br&gt;

What number times the square root of 2 would give us 16?&lt;br&gt;

In other words,&lt;br&gt;

{{{x*sqrt(2)=16}}}&lt;br&gt;

{{{x=16/sqrt(2)}}}&lt;br&gt;

{{{x=(16*sqrt(2))/(sqrt(2)*sqrt(2))}}}&lt;br&gt;

{{{x=(16*sqrt(2))/2}}}&lt;br&gt;

{{{x=8*sqrt(2)}}} which is the exact answer.&lt;br&gt;

I hope this helps!&lt;br&gt;</PRE>