Question 542179

{{{6x-3y=12}}} Start with the given equation.



{{{-3y=12-6x}}} Subtract {{{6x}}} from both sides.



{{{-3y=-6x+12}}} Rearrange the terms.



{{{y=(-6x+12)/(-3)}}} Divide both sides by {{{-3}}} to isolate y.



{{{y=((-6)/(-3))x+(12)/(-3)}}} Break up the fraction.



{{{y=2x-4}}} Reduce.



So the equation {{{y=2x-4}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=2}}} and the y-intercept is {{{b=-4}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-4\right)]



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