Question 541723
{{{(1/2)y=(1/3)y+2}}} Start with the given equation.



{{{6((1/cross(2))y)=6((1/cross(3))y+2)}}} Multiply both sides by the LCD {{{6}}} to clear any fractions.



{{{3y=2y+12}}} Distribute and multiply.



{{{3y-2y=12}}} Subtract {{{2y}}} from both sides.



{{{y=12}}} Combine like terms on the left side.



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Answer:


So the solution is {{{y=12}}} 



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