Question 542112

Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(2,13\right)]. So this means that {{{x[1]=2}}} and {{{y[1]=13}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(6,33\right)].  So this means that {{{x[2]=6}}} and {{{y[2]=33}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(33-13)/(6-2)}}} Plug in {{{y[2]=33}}}, {{{y[1]=13}}}, {{{x[2]=6}}}, and {{{x[1]=2}}}



{{{m=(20)/(6-2)}}} Subtract {{{13}}} from {{{33}}} to get {{{20}}}



{{{m=(20)/(4)}}} Subtract {{{2}}} from {{{6}}} to get {{{4}}}



{{{m=5}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(2,13\right)] and *[Tex \LARGE \left(6,33\right)] is {{{m=5}}}



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