Question 541729
the following function expresses profit in terms of the number of phones sold by a particular company:
P(x) = –x^2 + 110x – 1000
This function can be used to compute the profit (in thousands of dollars) from producing and selling a certain number, x, of thousands of smartphones.
Compute the following: P(5), P(50), and P(120). an Graph
:
P(5) = –x^2 + 110x – 1000
Substitute 5 for x:
P(5) = -5^2 + 110(5) – 1000
P(5) = -25 + 550 - 1000
P(5) = -475, a loss
:
P(50) = –x^2 + 110x – 1000
Substitute 50 for x:
P(50) = –50^2 + 110(50) – 1000
P(50) = -2500 + 5500 - 1000
P(50) = 2000, a profit
:
P(120), you can do this one, you can see on the graph, it will be a loss
:
Graph equation: y = -x^2 + 110x - 1000:
{{{ graph( 300, 200, -50, 150, -2500, 2500, -x^2+110x-1000) }}}