Question 541859
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Periodic compound interest:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ P\left(1\ +\ \frac{r}{n}\right)^{nt}]


Where


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A] represents the Future Value


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P] represents the Present Value (amount invested)


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r] represents the annual interest rate <i><b>expressed as a decimal</b></i>


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ n] represents the number of compounding periods per year (1 for annual, 2 for semiannual, 12 for monthly, etc.)


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ t] represents the number of years the money will be invested.


Continuous Compounding:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ Pe^{rt}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A,\,P,\,r,\,\text{and}\,t] as above


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ e] is the base of the natural logarithms


Plug in the values and do the arithmetic.  You will need your calculator if you want to get this done before Christmas.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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