Question 541620
Life is easy for that manager; he sells the same number of heads of lettuce every day.
Let the number of heads of lettuce sold daily be x, because that is the only mystery here, and is the unknown we are trying to find.
The store opens Monday withe 80 heads of lettuce on display.
As x sell on Monday, the day ends with {{{80-x}}} on display.
On Tuesday, before opening, the manager orders doubling the number of heads of lettuce that are on display. The store opens with {{{2(80-x)=160-2x}}} on display.
At the end on the day, the number of heads of lettuce that are on display is {{{160-2x-x=160-3x}}}.
On Wednesday, before opening, the manager orders tripling the number of heads of lettuce that are on display. The store opens with {{{3(160-3x)=480-9x}}} on display. Some were starting to look a little wilted on the outside, but that astute store manager, knew that he would still sell them. He sold x that day as usual.
At the end of the day the number of head of lettuce on display was
{{{480-9x-x=480-10x}}} and it was also zero.
That manager knew his sale patterns well, and he was so good at algebra too.
{{{480-10x=0}}} is the equation to solve.
You'll go through {{{480=10x}}} to {{{x=48}}}